What is the answer to ln(x)+ln(x-1)=ln(4x) ?

The answer to ln(x)+ln(x-1)=ln(4x) is x=5

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ln(x)+ln(x-1)=ln(4x)

ln (x) + ln (x - 1) = ln (4 x)

x = 5

Solution steps

ln (x) + ln (x - 1) = ln (4 x)

Apply log rules

x (x - 1) = 4 x

Solve

x (x - 1) = 4 x : x = 0, x = 5

x = 0, x = 5

Verify Solutions:

x = 0

False

, x = 5

True

The solution is

x = 5

ln (x) - ln (x - 2) = 1

lo g_{3} (x) + 2 = lo g_{3} (5)

lo g_{6} (x) = 2

lo g_{5} (x) = 4

lo g_{10} (5 x) = 3

What is the answer to ln(x)+ln(x-1)=ln(4x) ?
The answer to ln(x)+ln(x-1)=ln(4x) is x=5
Solve for x: ln(x)+ln(x-1)=ln(4x)
The solution is x=5