What is the answer to ln(x^4)-ln(x^2)=2 ?

The answer to ln(x^4)-ln(x^2)=2 is x=e,x=-e

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ln(x^4)-ln(x^2)=2

ln (x^{4}) - ln (x^{2}) = 2

x = e, x = - e

Decimal Notation

x = 2.71828 \dots, x = - 2.71828 \dots

Solution steps

ln (x^{4}) - ln (x^{2}) = 2

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

x^{4} = (x^{2})^{2}

ln ((x^{2})^{2}) - ln (x^{2}) = 2

Apply log rules

x^{2} = e^{2}

Solve

x^{2} = e^{2} : x = e, x = - e

x = e, x = - e

Verify Solutions:

x = e

True

, x = - e

True

The solutions are

x = e, x = - e

lo g_{10} (x) + lo g_{10} (x + 15) = 2

lo g_{x} (4) = 2

lo g_{x} (64) = 6

lo g_{2} (5 x + 7) = 5

lo g_{10} (4 x) = 2

What is the answer to ln(x^4)-ln(x^2)=2 ?
The answer to ln(x^4)-ln(x^2)=2 is x=e,x=-e
Solve for x: ln(x^4)-ln(x^2)=2
The solution is x=e,x=-e