What is the answer to ln(x^2-1)=0 ?

The answer to ln(x^2-1)=0 is x=sqrt(2),x=-sqrt(2)

Solve for x: ln(x^2-1)=0

The solution is x=sqrt(2),x=-sqrt(2)

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ln (x^{2} - 1) = 0

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

ln (x^{2} - 1) = 0

Apply log rules

x^{2} - 1 = 1

Solve

x^{2} - 1 = 1 : x = 2, x = - 2

x = 2, x = - 2

ln (\frac{15}{13 - 2 x}) = ln (x)

lo g_{5} (x) = - 3

lo g_{2} (lo g_{3} (x)) = 2

ln (x - 2) + ln (x + 1) = 2 ln (2)

lo g_{x} (32) = \frac{5}{2}

What is the answer to ln(x^2-1)=0 ?
The answer to ln(x^2-1)=0 is x=sqrt(2),x=-sqrt(2)
Solve for x: ln(x^2-1)=0
The solution is x=sqrt(2),x=-sqrt(2)