What is the answer to log_{3}(4x-5)=log_{3}(2x+1) ?

The answer to log_{3}(4x-5)=log_{3}(2x+1) is x=3

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log_{3}(4x-5)=log_{3}(2x+1)

lo g_{3} (4 x - 5) = lo g_{3} (2 x + 1)

x = 3

Solution steps

lo g_{3} (4 x - 5) = lo g_{3} (2 x + 1)

Apply log rules

4 x - 5 = 2 x + 1

Solve

4 x - 5 = 2 x + 1 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{2} (x) - 3 = 1

lo g_{2} (x) = 1

ln (x - 3) = 2

lo g_{x} (5) = \frac{1}{2}

4 = - lo g_{10} (x)

What is the answer to log_{3}(4x-5)=log_{3}(2x+1) ?
The answer to log_{3}(4x-5)=log_{3}(2x+1) is x=3
Solve for x: log_{3}(4x-5)=log_{3}(2x+1)
The solution is x=3