What is the answer to ln(3x)+ln(x+2)=0 ?

The answer to ln(3x)+ln(x+2)=0 is x=(-3+2sqrt(3))/3

Solve for x: ln(3x)+ln(x+2)=0

The solution is x=(-3+2sqrt(3))/3

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ln (3 x) + ln (x + 2) = 0

x = \frac{- 3 + 2 3}{3}

Decimal Notation

x = 0.15470 \dots

Solution steps

ln (3 x) + ln (x + 2) = 0

Apply log rules

3 x (x + 2) = 1

Solve

3 x (x + 2) = 1 : x = \frac{- 3 + 2 3}{3}, x = - \frac{3 + 2}{3}

x = \frac{- 3 + 2 3}{3}, x = - \frac{3 + 2}{3}

Verify Solutions:

x = \frac{- 3 + 2 3}{3}

True

, x = - \frac{3 + 2}{3}

False

The solution is

x = \frac{- 3 + 2 3}{3}

ln (x) + ln (x - 2) = ln (3)

lo g_{6} (x) = - 2

9 lo g_{x} (5) = lo g_{5} (x)

ln (x + 1) = 2

ln (x^{2}) = 14

What is the answer to ln(3x)+ln(x+2)=0 ?
The answer to ln(3x)+ln(x+2)=0 is x=(-3+2sqrt(3))/3
Solve for x: ln(3x)+ln(x+2)=0
The solution is x=(-3+2sqrt(3))/3