What is the answer to log_{2}(x+3)+log_{2}(x-3)=4 ?

The answer to log_{2}(x+3)+log_{2}(x-3)=4 is x=5

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log_{2}(x+3)+log_{2}(x-3)=4

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 4

x = 5

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 4

Apply log rules

(x + 3) (x - 3) = 16

Solve

(x + 3) (x - 3) = 16 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

False

The solution is

x = 5

lo g_{x} (81) = 2

lo g_{m} (32) = 5

lo g_{x} (81) = - 4

2 = ln (x)

lo g_{x} (4) = \frac{1}{2}

What is the answer to log_{2}(x+3)+log_{2}(x-3)=4 ?
The answer to log_{2}(x+3)+log_{2}(x-3)=4 is x=5
Solve for x: log_{2}(x+3)+log_{2}(x-3)=4
The solution is x=5