What is the answer to 2log_{2}(x)-log_{2}(x+3)=2 ?

The answer to 2log_{2}(x)-log_{2}(x+3)=2 is x=6

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2log_{2}(x)-log_{2}(x+3)=2

2 lo g_{2} (x) - lo g_{2} (x + 3) = 2

x = 6

Solution steps

2 lo g_{2} (x) - lo g_{2} (x + 3) = 2

Apply log rules

x^{2} = 4 (x + 3)

Solve

x^{2} = 4 (x + 3) : x = 6, x = - 2

x = 6, x = - 2

Verify Solutions:

x = 6

True

, x = - 2

False

The solution is

x = 6

ln (x^{2}) = 18

lo g_{4} (x) = 5

lo g_{81} (x) = \frac{1}{4}

lo g_{x} (125) = \frac{3}{2}

lo g_{3} (x + 4) - lo g_{3} (x - 1) = 2

What is the answer to 2log_{2}(x)-log_{2}(x+3)=2 ?
The answer to 2log_{2}(x)-log_{2}(x+3)=2 is x=6
Solve for x: 2log_{2}(x)-log_{2}(x+3)=2
The solution is x=6