What is the answer to log_{2}(x)-log_{4}(3x+4)=0 ?

The answer to log_{2}(x)-log_{4}(3x+4)=0 is x=4

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log_{2}(x)-log_{4}(3x+4)=0

lo g_{2} (x) - lo g_{4} (3 x + 4) = 0

x = 4

Solution steps

lo g_{2} (x) - lo g_{4} (3 x + 4) = 0

Apply log rules

x^{2} = 3 x + 4

Solve

x^{2} = 3 x + 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

False

The solution is

x = 4

ln (x) = ln (x)

lo g_{10} (x) = 0.66

ln (x) + ln (x - 5) = 0

lo g_{9} (x) = \frac{3}{2}

ln (x + 9) = 1

What is the answer to log_{2}(x)-log_{4}(3x+4)=0 ?
The answer to log_{2}(x)-log_{4}(3x+4)=0 is x=4
Solve for x: log_{2}(x)-log_{4}(3x+4)=0
The solution is x=4