What is the answer to 5+log_{2}(-5x)=9 ?

The answer to 5+log_{2}(-5x)=9 is x=-16/5

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5+log_{2}(-5x)=9

5 + lo g_{2} (- 5 x) = 9

x = - \frac{16}{5}

Decimal Notation

x = - 3.2

Solution steps

5 + lo g_{2} (- 5 x) = 9

Move

5

to the right side

lo g_{2} (- 5 x) = 4

Apply log rules

- 5 x = 16

Solve

- 5 x = 16 : x = - \frac{16}{5}

x = - \frac{16}{5}

Verify Solutions:

x = - \frac{16}{5}

True

The solution is

x = - \frac{16}{5}

lo g_{10} (x) = - 4

ln (x + 2) = 1

ln (x^{2}) = 16

lo g_{10} (x) = 0.3

lo g_{2} (x) + 21 lo g_{x} (2) = 10

What is the answer to 5+log_{2}(-5x)=9 ?
The answer to 5+log_{2}(-5x)=9 is x=-16/5
Solve for x: 5+log_{2}(-5x)=9
The solution is x=-16/5