What are the solutions to the equation 5x^2-26x+5=0 ?

The solutions to the equation 5x^2-26x+5=0 are x=5,x= 1/5

Find the zeros of 5x^2-26x+5=0

The zeros of 5x^2-26x+5=0 are x=5,x= 1/5

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5 x^{2} - 26 x + 5 = 0

x = 5, x = \frac{1}{5}

Decimal Notation

x = 5, x = 0.2

Solution steps

5 x^{2} - 26 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 \cdot 5 = 24

x_{1, 2} = \frac{- ( - 26 ) \pm 24}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 24}{2 \cdot 5}, x_{2} = \frac{- ( - 26 ) - 24}{2 \cdot 5}

x = \frac{- ( - 26 ) + 24}{2 \cdot 5} : 5

x = \frac{- ( - 26 ) - 24}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 5, x = \frac{1}{5}

lo g_{5} (\frac{1}{125})

\frac{1}{5} + [\frac{1}{10} - (\frac{3}{2} - \frac{6}{5}) + \frac{5}{4}]

49 v^{2} - 56 v + 16

(1.3 x - 0.6)^{2} = - 12

\frac{1}{3} + \frac{1}{7}

What are the solutions to the equation 5x^2-26x+5=0 ?
The solutions to the equation 5x^2-26x+5=0 are x=5,x= 1/5
Find the zeros of 5x^2-26x+5=0
The zeros of 5x^2-26x+5=0 are x=5,x= 1/5