What is the answer to ln(x-1)+ln(x+2)=1 ?

The answer to ln(x-1)+ln(x+2)=1 is x=(-1+sqrt(4e+9))/2

Solve for x: ln(x-1)+ln(x+2)=1

The solution is x=(-1+sqrt(4e+9))/2

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ln (x - 1) + ln (x + 2) = 1

x = \frac{- 1 + 4 e + 9}{2}

Decimal Notation

x = 1.72896 \dots

Solution steps

ln (x - 1) + ln (x + 2) = 1

Apply log rules

(x - 1) (x + 2) = e

Solve

(x - 1) (x + 2) = e : x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

Verify Solutions:

x = \frac{- 1 + 4 e + 9}{2}

True

, x = \frac{- 1 - 4 e + 9}{2}

False

The solution is

x = \frac{- 1 + 4 e + 9}{2}

5 lo g_{10} (x - 2) = 11

lo g_{x} (2) = 1

lo g_{2} (lo g_{x} (4)) = 1

1 = ln (x)

lo g_{10} (4 x - 8) = 2

What is the answer to ln(x-1)+ln(x+2)=1 ?
The answer to ln(x-1)+ln(x+2)=1 is x=(-1+sqrt(4e+9))/2
Solve for x: ln(x-1)+ln(x+2)=1
The solution is x=(-1+sqrt(4e+9))/2