What is the answer to log_{4}(x)+log_{4}(x+6)=2 ?

The answer to log_{4}(x)+log_{4}(x+6)=2 is x=2

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log_{4}(x)+log_{4}(x+6)=2

lo g_{4} (x) + lo g_{4} (x + 6) = 2

x = 2

Solution steps

lo g_{4} (x) + lo g_{4} (x + 6) = 2

Apply log rules

x (x + 6) = 16

Solve

x (x + 6) = 16 : x = 2, x = - 8

x = 2, x = - 8

Verify Solutions:

x = 2

True

, x = - 8

False

The solution is

x = 2

ln (x^{2}) = 20

lo g_{3} (4^{x}) = 1 - 2 x

lo g_{4} (x) = \frac{3}{2}

2 ln (x) = ln (x^{2})

lo g_{2} (x - 1) = 5

What is the answer to log_{4}(x)+log_{4}(x+6)=2 ?
The answer to log_{4}(x)+log_{4}(x+6)=2 is x=2
Solve for x: log_{4}(x)+log_{4}(x+6)=2
The solution is x=2