What is the answer to ln(-4-x)+ln(3)=ln(2-x) ?

The answer to ln(-4-x)+ln(3)=ln(2-x) is x=-7

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ln(-4-x)+ln(3)=ln(2-x)

ln (- 4 - x) + ln (3) = ln (2 - x)

x = - 7

Solution steps

ln (- 4 - x) + ln (3) = ln (2 - x)

Apply log rules

(- 4 - x) \cdot 3 = 2 - x

Solve

(- 4 - x) \cdot 3 = 2 - x : x = - 7

x = - 7

Verify Solutions:

x = - 7

True

The solution is

x = - 7

- 3 lo g_{2} (5 x) = - 12

- ln (x) = 0

x, ln (x + y^{2}) = y^{3}

lo g_{2} (x) = 7

2 ln (x) - ln (1 - x) = 2

What is the answer to ln(-4-x)+ln(3)=ln(2-x) ?
The answer to ln(-4-x)+ln(3)=ln(2-x) is x=-7
Solve for x: ln(-4-x)+ln(3)=ln(2-x)
The solution is x=-7