What is the answer to 1+log_{2}(-5x)=4 ?

The answer to 1+log_{2}(-5x)=4 is x=-8/5

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1+log_{2}(-5x)=4

1 + lo g_{2} (- 5 x) = 4

x = - \frac{8}{5}

Solution steps

1 + lo g_{2} (- 5 x) = 4

Move

1

to the right side

lo g_{2} (- 5 x) = 3

Apply log rules

- 5 x = 8

Solve

- 5 x = 8 : x = - \frac{8}{5}

x = - \frac{8}{5}

Verify Solutions:

x = - \frac{8}{5}

True

The solution is

x = - \frac{8}{5}

ln (x + 1) = 0

ln (x + 1) - ln (x) = 2

2 + lo g_{2} (x) = 15 lo g_{x} (2)

ln (\frac{10}{7 - 2 x}) = ln (2 x)

lo g_{4} (x) = - 3

What is the answer to 1+log_{2}(-5x)=4 ?
The answer to 1+log_{2}(-5x)=4 is x=-8/5
Solve for x: 1+log_{2}(-5x)=4
The solution is x=-8/5