What is the answer to log_{2}(x^2-x-1)=2 ?

The answer to log_{2}(x^2-x-1)=2 is x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

Solve for x: log_{2}(x^2-x-1)=2

The solution is x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

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lo g_{2} (x^{2} - x - 1) = 2

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

Decimal Notation

x = 2.79128 \dots, x = - 1.79128 \dots

Solution steps

lo g_{2} (x^{2} - x - 1) = 2

Apply log rules

x^{2} - x - 1 = 4

Solve

x^{2} - x - 1 = 4 : x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

lo g_{2} (2 x) = 2 lo g_{4} (x + 4)

lo g_{5} (2 x + 4) = 2

lo g_{10} (3 x + 5) = 2

ln (x) = 9

ln (x) = e

What is the answer to log_{2}(x^2-x-1)=2 ?
The answer to log_{2}(x^2-x-1)=2 is x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2
Solve for x: log_{2}(x^2-x-1)=2
The solution is x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2