What is the answer to log_{2}(x^2)-log_{x}(x)=7 ?

The answer to log_{2}(x^2)-log_{x}(x)=7 is x=16

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log_{2}(x^2)-log_{x}(x)=7

lo g_{2} (x^{2}) - lo g_{x} (x) = 7

x = 16

Solution steps

lo g_{2} (x^{2}) - lo g_{x} (x) = 7

Apply log rules

x^{2} = 256

Solve

x^{2} = 256 : x = 16, x = - 16

x = 16, x = - 16

Verify Solutions:

x = 16

True

, x = - 16

False

The solution is

x = 16

2 lo g_{3} (x + 15) - lo g_{3} (x) = 4

lo g_{2} (x + 2) - lo g_{2} (x - 5) = 3

ln (x - 5) = 1

5 lo g_{3} (x + 11) = 5

lo g_{5} (x + 7) = 1 - lo g_{5} (x + 3)

What is the answer to log_{2}(x^2)-log_{x}(x)=7 ?
The answer to log_{2}(x^2)-log_{x}(x)=7 is x=16
Solve for x: log_{2}(x^2)-log_{x}(x)=7
The solution is x=16