What is the answer to log_{2}(x+2)+log_{2}(x+5)=2 ?

The answer to log_{2}(x+2)+log_{2}(x+5)=2 is x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+2)+log_{2}(x+5)=2

lo g_{2} (x + 2) + lo g_{2} (x + 5) = 2

x = - 1

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x + 5) = 2

Apply log rules

(x + 2) (x + 5) = 4

Solve

(x + 2) (x + 5) = 4 : x = - 1, x = - 6

x = - 1, x = - 6

Verify Solutions:

x = - 1

True

, x = - 6

False

The solution is

x = - 1

lo g_{4} (x) = 9

lo g_{10} (x) = 1.5

ln (2 x) + ln (x - 2) = 2 ln (x)

24.72 = - 1.63 ln (x) + 12.613

4 = lo g_{b} (625)

What is the answer to log_{2}(x+2)+log_{2}(x+5)=2 ?
The answer to log_{2}(x+2)+log_{2}(x+5)=2 is x=-1
Solve for x: log_{2}(x+2)+log_{2}(x+5)=2
The solution is x=-1