What is the answer to ln(2b)=4ln(4b) ?

The answer to ln(2b)=4ln(4b) is b= 1/(e^{\frac{7ln(2)){3}}}

Solve for b: ln(2b)=4ln(4b)

The solution is b= 1/(e^{\frac{7ln(2)){3}}}

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ln (2 b) = 4 ln (4 b)

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Solution steps

ln (2 b) = 4 ln (4 b)

Apply log rules

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

lo g_{4} (4 - 3 x) = 3

lo g_{25} (x) = \frac{1}{2}

y, ln (y) = k t

lo g_{3} (x) = - 4

ln (x) + ln (x + 2) = 4

What is the answer to ln(2b)=4ln(4b) ?
The answer to ln(2b)=4ln(4b) is b= 1/(e^{\frac{7ln(2)){3}}}
Solve for b: ln(2b)=4ln(4b)
The solution is b= 1/(e^{\frac{7ln(2)){3}}}