What is the answer to log_{2}(x+2)+log_{2}(x-1)=2 ?

The answer to log_{2}(x+2)+log_{2}(x-1)=2 is x=2

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log_{2}(x+2)+log_{2}(x-1)=2

lo g_{2} (x + 2) + lo g_{2} (x - 1) = 2

x = 2

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x - 1) = 2

Apply log rules

(x + 2) (x - 1) = 4

Solve

(x + 2) (x - 1) = 4 : x = 2, x = - 3

x = 2, x = - 3

Verify Solutions:

x = 2

True

, x = - 3

False

The solution is

x = 2

lo g_{10} (1 + x) = 3

lo g_{2} (x) = 8 + 9 lo g_{x} (2)

ln (3 x - 2) + ln (x - 1) = 2 ln (x)

lo g_{5} (x) = - 1

lo g_{5} (t^{7}) = 5

What is the answer to log_{2}(x+2)+log_{2}(x-1)=2 ?
The answer to log_{2}(x+2)+log_{2}(x-1)=2 is x=2
Solve for x: log_{2}(x+2)+log_{2}(x-1)=2
The solution is x=2