What is the answer to 5log_{4}(x)-log_{4}(3)=2 ?

The answer to 5log_{4}(x)-log_{4}(3)=2 is x=4^{(2+log_{4}(3))/5}

Solve for x: 5log_{4}(x)-log_{4}(3)=2

The solution is x=4^{(2+log_{4}(3))/5}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 lo g_{4} (x) - lo g_{4} (3) = 2

x = 4^{\frac{2 + l o g _{4} ( 3 )}{5}}

Decimal Notation

x = 2.16894 \dots

Solution steps

5 lo g_{4} (x) - lo g_{4} (3) = 2

Move

lo g_{4} (3)

to the right side

5 lo g_{4} (x) = 2 + lo g_{4} (3)

Divide both sides by

5

lo g_{4} (x) = \frac{2 + lo g _{4} ( 3 )}{5}

Apply log rules

x = 4^{\frac{2 + l o g _{4} ( 3 )}{5}}

Verify Solutions:

x = 4^{\frac{2 + l o g _{4} ( 3 )}{5}}

True

The solution is

x = 4^{\frac{2 + l o g _{4} ( 3 )}{5}}

lo g_{x - 1} (x + 5) = 2

lo g_{3} (2 - x) = 3

lo g_{x} (27) = \frac{3}{2}

ln (x^{2}) = (ln (x))^{2}

lo g_{10} (c) = 10

What is the answer to 5log_{4}(x)-log_{4}(3)=2 ?
The answer to 5log_{4}(x)-log_{4}(3)=2 is x=4^{(2+log_{4}(3))/5}
Solve for x: 5log_{4}(x)-log_{4}(3)=2
The solution is x=4^{(2+log_{4}(3))/5}