What is the answer to log_{10}(7)+log_{10}(x-4)=1 ?

The answer to log_{10}(7)+log_{10}(x-4)=1 is x= 38/7

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log_{10}(7)+log_{10}(x-4)=1

lo g_{10} (7) + lo g_{10} (x - 4) = 1

x = \frac{38}{7}

Solution steps

lo g_{10} (7) + lo g_{10} (x - 4) = 1

Move

lo g_{10} (7)

to the right side

lo g_{10} (x - 4) = 1 - lo g_{10} (7)

Apply log rules

x - 4 = \frac{10}{7}

Solve

x - 4 = \frac{10}{7} : x = \frac{38}{7}

x = \frac{38}{7}

Verify Solutions:

x = \frac{38}{7}

True

The solution is

x = \frac{38}{7}

lo g_{100} (x) = \frac{1}{2}

lo g_{2} (x + 3) = 2

- 5 + 2 ln (3 x) = 5

lo g_{2} (x + 3) = 2 - lo g_{2} (x + 6)

4 + 3 lo g_{10} (2 x) = 16

What is the answer to log_{10}(7)+log_{10}(x-4)=1 ?
The answer to log_{10}(7)+log_{10}(x-4)=1 is x= 38/7
Solve for x: log_{10}(7)+log_{10}(x-4)=1
The solution is x= 38/7