What is the answer to log_{10}(2x)=-1 ?

The answer to log_{10}(2x)=-1 is x= 1/20

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log_{10}(2x)=-1

lo g_{10} (2 x) = - 1

x = \frac{1}{20}

Solution steps

lo g_{10} (2 x) = - 1

Apply log rules

2 x = \frac{1}{10}

Solve

2 x = \frac{1}{10} : x = \frac{1}{20}

x = \frac{1}{20}

ln (x) - 1 = ln (5 + x) - 4

a, lo g_{a} (b) = c

lo g_{4} (3 x + 1) = 2

lo g_{x} (4) = \frac{1}{3}

lo g_{2} (x + 4) = 3 - lo g_{2} (x + 6)

What is the answer to log_{10}(2x)=-1 ?
The answer to log_{10}(2x)=-1 is x= 1/20
Solve for x: log_{10}(2x)=-1
The solution is x= 1/20