What is the answer to ln(x+1)+ln(x-1)=3 ?

The answer to ln(x+1)+ln(x-1)=3 is x=sqrt(e^3+1)

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ln(x+1)+ln(x-1)=3

ln (x + 1) + ln (x - 1) = 3

x = e^{3} + 1

Solution steps

ln (x + 1) + ln (x - 1) = 3

Apply log rules

(x + 1) (x - 1) = e^{3}

Solve

(x + 1) (x - 1) = e^{3} : x = e^{3} + 1, x = - e^{3} + 1

x = e^{3} + 1, x = - e^{3} + 1

Verify Solutions:

x = e^{3} + 1

True

, x = - e^{3} + 1

False

The solution is

x = e^{3} + 1

lo g_{2} (x + 5) - lo g_{2} (x - 2) = 3

lo g_{2} (- 3 x + 4) = 4

ln (x) = - 0.123

(ln (x))^{2} - ln (x^{3}) - 8 = 2

ln (ln (x)) = 4

What is the answer to ln(x+1)+ln(x-1)=3 ?
The answer to ln(x+1)+ln(x-1)=3 is x=sqrt(e^3+1)
Solve for x: ln(x+1)+ln(x-1)=3
The solution is x=sqrt(e^3+1)