What is the answer to log_{3}(81)-log_{3}(x-4)=2 ?

The answer to log_{3}(81)-log_{3}(x-4)=2 is x=13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(81)-log_{3}(x-4)=2

lo g_{3} (81) - lo g_{3} (x - 4) = 2

x = 13

Solution steps

lo g_{3} (81) - lo g_{3} (x - 4) = 2

Move

lo g_{3} (81)

to the right side

- lo g_{3} (x - 4) = 2 - lo g_{3} (81)

Divide both sides by

- 1

lo g_{3} (x - 4) = - 2 + lo g_{3} (81)

Apply log rules

x - 4 = 9

Solve

x - 4 = 9 : x = 13

x = 13

Verify Solutions:

x = 13

True

The solution is

x = 13

ln (3 x - 12) = 4

lo g_{2} (6 - x) - lo g_{2} (4 - x) = 2

lo g_{5} (x - 4) = 1 - lo g_{5} (x - 8)

ln (x + 2) + ln (x) = ln (6 x) - ln (6)

ln (x^{2}) = 0

What is the answer to log_{3}(81)-log_{3}(x-4)=2 ?
The answer to log_{3}(81)-log_{3}(x-4)=2 is x=13
Solve for x: log_{3}(81)-log_{3}(x-4)=2
The solution is x=13