What are the solutions to the equation x^2+15x=-50 ?

The solutions to the equation x^2+15x=-50 are x=-5,x=-10

Find the zeros of x^2+15x=-50

The zeros of x^2+15x=-50 are x=-5,x=-10

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x^{2} + 15 x = - 50

x = - 5, x = - 10

Solution steps

x^{2} + 15 x = - 50

Move

50

to the left side

x^{2} + 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 5}{2 \cdot 1}, x_{2} = \frac{- 15 - 5}{2 \cdot 1}

x = \frac{- 15 + 5}{2 \cdot 1} : - 5

x = \frac{- 15 - 5}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 5, x = - 10

4 (- 4 x - 1) + x + 3 = 44

\frac{1}{2} e^{- 2 x} \cdot e^{2 x}

\frac{1300 \cdot 9.8 1 ^{2}}{120}

e^{\frac{3 iπ}{2}}

23 x + 22 = 21 x + 14

What are the solutions to the equation x^2+15x=-50 ?
The solutions to the equation x^2+15x=-50 are x=-5,x=-10
Find the zeros of x^2+15x=-50
The zeros of x^2+15x=-50 are x=-5,x=-10