What is the answer to log_{5}(x+6)+log_{5}(x+2)=1 ?

The answer to log_{5}(x+6)+log_{5}(x+2)=1 is x=-1

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log_{5}(x+6)+log_{5}(x+2)=1

lo g_{5} (x + 6) + lo g_{5} (x + 2) = 1

x = - 1

Solution steps

lo g_{5} (x + 6) + lo g_{5} (x + 2) = 1

Apply log rules

(x + 6) (x + 2) = 5

Solve

(x + 6) (x + 2) = 5 : x = - 1, x = - 7

x = - 1, x = - 7

Verify Solutions:

x = - 1

True

, x = - 7

False

The solution is

x = - 1

lo g_{10} (x) = 6

ln (y) = 3

4 lo g_{2} (x + 12) = 12

lo g_{2} (3 x - 2) - lo g_{2} (x - 5) = 4

lo g_{9} (x) = 3

What is the answer to log_{5}(x+6)+log_{5}(x+2)=1 ?
The answer to log_{5}(x+6)+log_{5}(x+2)=1 is x=-1
Solve for x: log_{5}(x+6)+log_{5}(x+2)=1
The solution is x=-1