What is the answer to 2ln(x)+1=0 ?

The answer to 2ln(x)+1=0 is x= 1/(sqrt(e))

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2ln(x)+1=0

2 ln (x) + 1 = 0

x = \frac{1}{e}

Decimal Notation

x = 0.60653 \dots

Solution steps

2 ln (x) + 1 = 0

Move

1

to the right side

2 ln (x) = - 1

Divide both sides by

2

ln (x) = - \frac{1}{2}

Apply log rules

x = \frac{1}{e}

Verify Solutions:

x = \frac{1}{e}

True

The solution is

x = \frac{1}{e}

lo g_{2} (x + 4) - lo g_{2} (x - 1) = 1

lo g_{3} (y) + 4 lo g_{y} (3) = 4

lo g_{\frac{1}{2}} (x) = - 1

lo g_{10} (4 x) + lo g_{10} (8 x) = 1

lo g_{2} (n) = 3.6 \cdot 1 0^{13}