What is the answer to log_{4}(x+1)=log_{2}(x-1) ?

The answer to log_{4}(x+1)=log_{2}(x-1) is x=3

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log_{4}(x+1)=log_{2}(x-1)

lo g_{4} (x + 1) = lo g_{2} (x - 1)

x = 3

Solution steps

lo g_{4} (x + 1) = lo g_{2} (x - 1)

Apply log rules

x + 1 = (x - 1)^{2}

Solve

x + 1 = (x - 1)^{2} : x = 3, x = 0

x = 3, x = 0

Verify Solutions:

x = 3

True

, x = 0

False

The solution is

x = 3

ln (ln (x)) = 5

x^{l o g_{3} (x)} = 27 x^{2}

lo g_{8} (2) + lo g_{8} (4 x^{2}) = 1

lo g_{8} (x) = 3

lo g_{4} (x) + lo g_{x} (4) = 2.5

What is the answer to log_{4}(x+1)=log_{2}(x-1) ?
The answer to log_{4}(x+1)=log_{2}(x-1) is x=3
Solve for x: log_{4}(x+1)=log_{2}(x-1)
The solution is x=3