What is the answer to log_{16}(x)=(log_{4}(x))^2 ?

The answer to log_{16}(x)=(log_{4}(x))^2 is x=2,x=1

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log_{16}(x)=(log_{4}(x))^2

lo g_{16} (x) = (lo g_{4} (x))^{2}

x = 2, x = 1

Solution steps

lo g_{16} (x) = (lo g_{4} (x))^{2}

Apply log rules

lo g_{16} (x) = 4 lo g_{16} (x)^{2}

Rewrite the equation with

lo g_{16} (x) = u

u = 4 u^{2}

Solve

u = 4 u^{2} : u = \frac{1}{4}, u = 0

u = \frac{1}{4}, u = 0

Substitute back

u = lo g_{16} (x),

solve for

x

Solve

lo g_{16} (x) = \frac{1}{4} : x = 2

Solve

lo g_{16} (x) = 0 : x = 1

x = 2, x = 1

Verify Solutions:

x = 2

True

, x = 1

True

The solutions are

x = 2, x = 1

lo g_{10} (x) = 7

ln (y) = 0

ln (x + 1) + ln (x) = ln (6)

lo g_{3} (x) = 2

lo g_{2} (x - 3) = 2 - lo g_{2} (x - 6)

What is the answer to log_{16}(x)=(log_{4}(x))^2 ?
The answer to log_{16}(x)=(log_{4}(x))^2 is x=2,x=1
Solve for x: log_{16}(x)=(log_{4}(x))^2
The solution is x=2,x=1