What is the answer to ln(x)+ln(2x)=3 ?

The answer to ln(x)+ln(2x)=3 is x=e^{(3-ln(2))/2}

Solve for x: ln(x)+ln(2x)=3

The solution is x=e^{(3-ln(2))/2}

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ln (x) + ln (2 x) = 3

x = e^{\frac{3 - l n ( 2 )}{2}}

Decimal Notation

x = 3.16903 \dots

Solution steps

ln (x) + ln (2 x) = 3

Apply log rules

x = e^{\frac{3 - l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{3 - l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{3 - l n ( 2 )}{2}}

lo g_{7} (x + 6) - 1 = - lo g_{7} (x)

lo g_{64} (x) = \frac{1}{3}

lo g_{4} (x) = - 1

ln (x - 2) + ln (2 x - 3) = 2 ln (x)

0.912 = ln (x^{3})

What is the answer to ln(x)+ln(2x)=3 ?
The answer to ln(x)+ln(2x)=3 is x=e^{(3-ln(2))/2}
Solve for x: ln(x)+ln(2x)=3
The solution is x=e^{(3-ln(2))/2}