What is the answer to log_{2}(x)+log_{4}(x)=9 ?

The answer to log_{2}(x)+log_{4}(x)=9 is x=64

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log_{2}(x)+log_{4}(x)=9

lo g_{2} (x) + lo g_{4} (x) = 9

x = 64

Solution steps

lo g_{2} (x) + lo g_{4} (x) = 9

Apply log rules

x = 64

Verify Solutions:

x = 64

True

The solution is

x = 64

lo g_{2} (y^{3}) = 6

lo g_{2} (x + 4) + lo g_{2} (x + 3) = 1

lo g_{a} (2) = \frac{1}{2}

lo g_{10} (x + 9) = 2 + lo g_{10} (x)

lo g_{3} (- 2 x + 8) = 1

What is the answer to log_{2}(x)+log_{4}(x)=9 ?
The answer to log_{2}(x)+log_{4}(x)=9 is x=64
Solve for x: log_{2}(x)+log_{4}(x)=9
The solution is x=64