What is the answer to log_{2}(x-3)+log_{2}(x+4)=3 ?

The answer to log_{2}(x-3)+log_{2}(x+4)=3 is x=4

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log_{2}(x-3)+log_{2}(x+4)=3

lo g_{2} (x - 3) + lo g_{2} (x + 4) = 3

x = 4

Solution steps

lo g_{2} (x - 3) + lo g_{2} (x + 4) = 3

Apply log rules

(x - 3) (x + 4) = 8

Solve

(x - 3) (x + 4) = 8 : x = 4, x = - 5

x = 4, x = - 5

Verify Solutions:

x = 4

True

, x = - 5

False

The solution is

x = 4

2 ln (x) = ln (6 - x) + ln (3)

lo g_{10} (x) = \frac{1}{2}

lo g_{x} (512) = 3

lo g_{x} (5) = \frac{1}{3}

3 ln (t) = 5

What is the answer to log_{2}(x-3)+log_{2}(x+4)=3 ?
The answer to log_{2}(x-3)+log_{2}(x+4)=3 is x=4
Solve for x: log_{2}(x-3)+log_{2}(x+4)=3
The solution is x=4