What is the answer to ln(x)+ln(x-6)=1 ?

The answer to ln(x)+ln(x-6)=1 is x=(6+sqrt(36+4e))/2

Solve for x: ln(x)+ln(x-6)=1

The solution is x=(6+sqrt(36+4e))/2

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ln (x) + ln (x - 6) = 1

x = \frac{6 + 36 + 4 e}{2}

Solution steps

ln (x) + ln (x - 6) = 1

Apply log rules

x (x - 6) = e

Solve

x (x - 6) = e : x = \frac{6 + 36 + 4 e}{2}, x = \frac{6 - 36 + 4 e}{2}

x = \frac{6 + 36 + 4 e}{2}, x = \frac{6 - 36 + 4 e}{2}

Verify Solutions:

x = \frac{6 + 36 + 4 e}{2}

True

, x = \frac{6 - 36 + 4 e}{2}

False

The solution is

x = \frac{6 + 36 + 4 e}{2}

2 lo g_{4} (x) - lo g_{4} (x + 5) = 2

x, ln (x) = 2

x, ln (x) = 0

lo g_{2} (x + 1) = 1 + 6 lo g_{x + 1} (2)

lo g_{10} (x + 10) = 2

What is the answer to ln(x)+ln(x-6)=1 ?
The answer to ln(x)+ln(x-6)=1 is x=(6+sqrt(36+4e))/2
Solve for x: ln(x)+ln(x-6)=1
The solution is x=(6+sqrt(36+4e))/2