What are the solutions to the equation 5/7 x^2+2x+15/5 =0 ?

The solutions to the equation 5/7 x^2+2x+15/5 =0 are x=-7/5+i(2sqrt(14))/5 ,x=-7/5-i(2sqrt(14))/5

Find the zeros of 5/7 x^2+2x+15/5 =0

The zeros of 5/7 x^2+2x+15/5 =0 are x=-7/5+i(2sqrt(14))/5 ,x=-7/5-i(2sqrt(14))/5

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\frac{5}{7} x^{2} + 2 x + \frac{15}{5} = 0

x = - \frac{7}{5} + i \frac{2 14}{5}, x = - \frac{7}{5} - i \frac{2 14}{5}

Solution steps

\frac{5}{7} x^{2} + 2 x + \frac{15}{5} = 0

Find Least Common Multiplier of

7, 5 : 35

Multiply by LCM=

35

\frac{5}{7} x^{2} \cdot 35 + 2 x \cdot 35 + \frac{15}{5} \cdot 35 = 0 \cdot 35

Simplify

25 x^{2} + 70 x + 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 25 \cdot 105}{2 \cdot 25}

Simplify

7 0^{2} - 4 \cdot 25 \cdot 105 : 2014 i

x_{1, 2} = \frac{- 70 \pm 20 14 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 70 + 20 14 i}{2 \cdot 25}, x_{2} = \frac{- 70 - 20 14 i}{2 \cdot 25}

x = \frac{- 70 + 20 14 i}{2 \cdot 25} : - \frac{7}{5} + i \frac{2 14}{5}

x = \frac{- 70 - 20 14 i}{2 \cdot 25} : - \frac{7}{5} - i \frac{2 14}{5}

The solutions to the quadratic equation are:

x = - \frac{7}{5} + i \frac{2 14}{5}, x = - \frac{7}{5} - i \frac{2 14}{5}

\frac{∣ - 7 n + 7 ∣}{10} = 1

lo g_{2} (x - 1) < 4

8 x^{2} - 3 x

(- \frac{4}{5})^{- 2}

\frac{12 x}{3} = \frac{3 x}{2} + 2

What are the solutions to the equation 5/7 x^2+2x+15/5 =0 ?
The solutions to the equation 5/7 x^2+2x+15/5 =0 are x=-7/5+i(2sqrt(14))/5 ,x=-7/5-i(2sqrt(14))/5
Find the zeros of 5/7 x^2+2x+15/5 =0
The zeros of 5/7 x^2+2x+15/5 =0 are x=-7/5+i(2sqrt(14))/5 ,x=-7/5-i(2sqrt(14))/5