What is the answer to log_{2}(x)+log_{2}(-4x+12)=3 ?

The answer to log_{2}(x)+log_{2}(-4x+12)=3 is x=1,x=2

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log_{2}(x)+log_{2}(-4x+12)=3

lo g_{2} (x) + lo g_{2} (- 4 x + 12) = 3

x = 1, x = 2

Solution steps

lo g_{2} (x) + lo g_{2} (- 4 x + 12) = 3

Apply log rules

x (- 4 x + 12) = 8

Solve

x (- 4 x + 12) = 8 : x = 1, x = 2

x = 1, x = 2

Verify Solutions:

x = 1

True

, x = 2

True

The solutions are

x = 1, x = 2

lo g_{4} (4 x) - lo g_{4} (2 x - 4) = 3

lo g_{5} (x) = 1

lo g_{\frac{2}{3}} (x) = - 2

lo g_{10} (7 x) = 2

ln (x + 1) = 3

What is the answer to log_{2}(x)+log_{2}(-4x+12)=3 ?
The answer to log_{2}(x)+log_{2}(-4x+12)=3 is x=1,x=2
Solve for x: log_{2}(x)+log_{2}(-4x+12)=3
The solution is x=1,x=2