What is the answer to ln(3/(t-5))=1.92 ?

The answer to ln(3/(t-5))=1.92 is t= 3/(e^{1.92)}+5

Solve for t: ln(3/(t-5))=1.92

The solution is t= 3/(e^{1.92)}+5

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ln (\frac{3}{t - 5}) = 1.92

t = \frac{3}{e ^{1.92}} + 5

Solution steps

ln (\frac{3}{t - 5}) = 1.92

Apply log rules

\frac{3}{t - 5} = e^{1.92}

Multiply both sides by

t - 5

\frac{3}{t - 5} (t - 5) = e^{1.92} (t - 5)

Simplify

3 = e^{1.92} (t - 5)

Solve

3 = e^{1.92} (t - 5) : t = \frac{3}{e ^{1.92}} + 5

t = \frac{3}{e ^{1.92}} + 5

Verify Solutions:

t = \frac{3}{e ^{1.92}} + 5

True

The solution is

t = \frac{3}{e ^{1.92}} + 5

ln (x - 2) = 0

lo g_{4} (2 x - 10) = \frac{1}{2}

lo g_{9} (x) + lo g_{3} (x) = 3

lo g_{y} (32) = 5

8 lo g_{10} (y) = 8

What is the answer to ln(3/(t-5))=1.92 ?
The answer to ln(3/(t-5))=1.92 is t= 3/(e^{1.92)}+5
Solve for t: ln(3/(t-5))=1.92
The solution is t= 3/(e^{1.92)}+5