What is the answer to ln(x-2)+ln(12-x)=0 ?

The answer to ln(x-2)+ln(12-x)=0 is x=7-2sqrt(6),x=7+2sqrt(6)

Solve for x: ln(x-2)+ln(12-x)=0

The solution is x=7-2sqrt(6),x=7+2sqrt(6)

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ln (x - 2) + ln (12 - x) = 0

x = 7 - 26, x = 7 + 26

Solution steps

ln (x - 2) + ln (12 - x) = 0

Apply log rules

(x - 2) (12 - x) = 1

Solve

(x - 2) (12 - x) = 1 : x = 7 - 26, x = 7 + 26

x = 7 - 26, x = 7 + 26

Verify Solutions:

x = 7 - 26

True

, x = 7 + 26

True

The solutions are

x = 7 - 26, x = 7 + 26

lo g_{8} (x - 5) = \frac{2}{3}

lo g_{10} (x + ln (x)) = 1

lo g_{5} (4 x) = 2

lo g_{x} (5) = 2

lo g_{5} (x - 6) = 1 - lo g_{5} (x - 2)

What is the answer to ln(x-2)+ln(12-x)=0 ?
The answer to ln(x-2)+ln(12-x)=0 is x=7-2sqrt(6),x=7+2sqrt(6)
Solve for x: ln(x-2)+ln(12-x)=0
The solution is x=7-2sqrt(6),x=7+2sqrt(6)