What is the answer to log_{10}(x)-log_{10}(6)=2 ?

The answer to log_{10}(x)-log_{10}(6)=2 is x=600

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x)-log_{10}(6)=2

lo g_{10} (x) - lo g_{10} (6) = 2

x = 600

Solution steps

lo g_{10} (x) - lo g_{10} (6) = 2

Move

lo g_{10} (6)

to the right side

lo g_{10} (x) = 2 + lo g_{10} (6)

Apply log rules

x = 600

Verify Solutions:

x = 600

True

The solution is

x = 600

lo g_{2} (x + 5) = 2 - lo g_{2} (x + 2)

lo g_{6} (x + 8) + lo g_{6} (x - 8) = 2

lo g_{5} (- 3 x + 5) = 3

- 7 + lo g_{3} (x + 7) = - 4

2 ln (x) + 1 = ln (2 x)

What is the answer to log_{10}(x)-log_{10}(6)=2 ?
The answer to log_{10}(x)-log_{10}(6)=2 is x=600
Solve for x: log_{10}(x)-log_{10}(6)=2
The solution is x=600