What is the answer to 5=log_{b}(32) ?

The answer to 5=log_{b}(32) is b=2

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5=log_{b}(32)

5 = lo g_{b} (32)

b = 2

Solution steps

5 = lo g_{b} (32)

Apply log rules

5 = \frac{1}{lo g _{32} ( b )}

Multiply both sides by

lo g_{32} (b)

5 lo g_{32} (b) = \frac{1}{lo g _{32} ( b )} lo g_{32} (b)

Simplify

5 lo g_{32} (b) = 1

Divide both sides by

5

lo g_{32} (b) = \frac{1}{5}

Apply log rules

b = 2

Verify Solutions:

b = 2

True

The solution is

b = 2

lo g_{2} (x + 3) = - 1

lo g_{6} (x) = 4

y, ln (y) = 9 t + 2

7 + lo g_{4} (- 5 x) = 9

ln (x - 3) - 2 ln (3) = 2