What is the answer to log_{4}(x)+log_{4}(x^2)=5 ?

The answer to log_{4}(x)+log_{4}(x^2)=5 is x=4*4^{2/3}

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log_{4}(x)+log_{4}(x^2)=5

lo g_{4} (x) + lo g_{4} (x^{2}) = 5

x = 4 \cdot 4^{\frac{2}{3}}

Solution steps

lo g_{4} (x) + lo g_{4} (x^{2}) = 5

Apply log rules

x = 4 \cdot 4^{\frac{2}{3}}

Verify Solutions:

x = 4 \cdot 4^{\frac{2}{3}}

True

The solution is

x = 4 \cdot 4^{\frac{2}{3}}

lo g_{2} (y) = 3

ln (x + 3) + ln (x + 7) = ln (77)

0.5 = lo g_{10} (x)

ln (x) = e^{2}

lo g_{2} (x - 7) = 3 - lo g_{2} (x - 5)

What is the answer to log_{4}(x)+log_{4}(x^2)=5 ?
The answer to log_{4}(x)+log_{4}(x^2)=5 is x=4*4^{2/3}
Solve for x: log_{4}(x)+log_{4}(x^2)=5
The solution is x=4*4^{2/3}