What is the answer to 2log_{4}(2-x)-log_{4}(x+5)=1 ?

The answer to 2log_{4}(2-x)-log_{4}(x+5)=1 is x=4(1-sqrt(2))

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2log_{4}(2-x)-log_{4}(x+5)=1

2 lo g_{4} (2 - x) - lo g_{4} (x + 5) = 1

x = 4 (1 - 2)

Decimal Notation

x = - 1.65685 \dots

Solution steps

2 lo g_{4} (2 - x) - lo g_{4} (x + 5) = 1

Apply log rules

(2 - x)^{2} = 4 (x + 5)

Solve

(2 - x)^{2} = 4 (x + 5) : x = 4 (1 + 2), x = 4 (1 - 2)

x = 4 (1 + 2), x = 4 (1 - 2)

Verify Solutions:

x = 4 (1 + 2)

False

, x = 4 (1 - 2)

True

The solution is

x = 4 (1 - 2)

lo g_{4} (x) = 4

lo g_{10} (3 x + 4) = 3

lo g_{5} (m x) = c

0.86 = lo g_{10} (x)

ln (8 x - 16) - 2 ln (x) = 0

What is the answer to 2log_{4}(2-x)-log_{4}(x+5)=1 ?
The answer to 2log_{4}(2-x)-log_{4}(x+5)=1 is x=4(1-sqrt(2))
Solve for x: 2log_{4}(2-x)-log_{4}(x+5)=1
The solution is x=4(1-sqrt(2))