What is the answer to log_{2}(x)+log_{3}(x)=1 ?

The answer to log_{2}(x)+log_{3}(x)=1 is x=3^{(log_{3}(2))/(1+log_{3)(2)}}

Solve for x: log_{2}(x)+log_{3}(x)=1

The solution is x=3^{(log_{3}(2))/(1+log_{3)(2)}}

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lo g_{2} (x) + lo g_{3} (x) = 1

x = 3^{\frac{l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Decimal Notation

x = 1.52959 \dots

Solution steps

lo g_{2} (x) + lo g_{3} (x) = 1

Apply log rules

x = 3^{\frac{l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Verify Solutions:

x = 3^{\frac{l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

True

The solution is

x = 3^{\frac{l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

lo g_{2} (x) = 9

lo g_{2} (x) = - \frac{1}{2}

ln (- x) = ln (x^{2} - 6)

0.38 = lo g_{10} (x)

lo g_{10} (x) - lo g_{10} (x + 3) = 1

What is the answer to log_{2}(x)+log_{3}(x)=1 ?
The answer to log_{2}(x)+log_{3}(x)=1 is x=3^{(log_{3}(2))/(1+log_{3)(2)}}
Solve for x: log_{2}(x)+log_{3}(x)=1
The solution is x=3^{(log_{3}(2))/(1+log_{3)(2)}}