What is the answer to log_{3}(p)+log_{27}(3p)=-1 ?

The answer to log_{3}(p)+log_{27}(3p)=-1 is p= 1/3

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log_{3}(p)+log_{27}(3p)=-1

lo g_{3} (p) + lo g_{27} (3 p) = - 1

p = \frac{1}{3}

Decimal Notation

p = 0.33333 \dots

Solution steps

lo g_{3} (p) + lo g_{27} (3 p) = - 1

Apply log rules

p = \frac{1}{3}

Verify Solutions:

p = \frac{1}{3}

True

The solution is

p = \frac{1}{3}

4 ln (5 x + 3) - 11 = 13

lo g_{6} (4 (x - 1)) = 2

2 lo g_{10} (x) = 2

lo g_{10} (3 x) = 2

ln (x + 2) - ln (x) = 1

What is the answer to log_{3}(p)+log_{27}(3p)=-1 ?
The answer to log_{3}(p)+log_{27}(3p)=-1 is p= 1/3
Solve for p: log_{3}(p)+log_{27}(3p)=-1
The solution is p= 1/3