What is the answer to log_{3}(x^2+3x-1)=2 ?

The answer to log_{3}(x^2+3x-1)=2 is x=2,x=-5

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log_{3}(x^2+3x-1)=2

lo g_{3} (x^{2} + 3 x - 1) = 2

x = 2, x = - 5

Solution steps

lo g_{3} (x^{2} + 3 x - 1) = 2

Apply log rules

x^{2} + 3 x - 1 = 9

Solve

x^{2} + 3 x - 1 = 9 : x = 2, x = - 5

x = 2, x = - 5

0 = lo g_{3} (- x - 1)

lo g_{x} (2) = \frac{1}{3}

lo g_{4} (- 3 x + 7) = 1

lo g_{6} (x - 8) = 2 - lo g_{6} (x + 8)

lo g_{10} (lo g_{10} (x)) = 1

What is the answer to log_{3}(x^2+3x-1)=2 ?
The answer to log_{3}(x^2+3x-1)=2 is x=2,x=-5
Solve for x: log_{3}(x^2+3x-1)=2
The solution is x=2,x=-5