What is the answer to log_{10}(x+8)+log_{10}(9)=1 ?

The answer to log_{10}(x+8)+log_{10}(9)=1 is x=-62/9

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log_{10}(x+8)+log_{10}(9)=1

lo g_{10} (x + 8) + lo g_{10} (9) = 1

x = - \frac{62}{9}

Decimal Notation

x = - 6.88888 \dots

Solution steps

lo g_{10} (x + 8) + lo g_{10} (9) = 1

Move

lo g_{10} (9)

to the right side

lo g_{10} (x + 8) = 1 - lo g_{10} (9)

Apply log rules

x + 8 = \frac{10}{9}

Solve

x + 8 = \frac{10}{9} : x = - \frac{62}{9}

x = - \frac{62}{9}

Verify Solutions:

x = - \frac{62}{9}

True

The solution is

x = - \frac{62}{9}

lo g_{10} (x) - lo g_{10} (x + 3) = - 1

x \cdot ln (x) = 0

ln (5 x + 1) + ln (x) = ln (4)

lo g_{3} (4 x - 2) = 3

lo g_{\frac{1}{4}} (x) = 2

What is the answer to log_{10}(x+8)+log_{10}(9)=1 ?
The answer to log_{10}(x+8)+log_{10}(9)=1 is x=-62/9
Solve for x: log_{10}(x+8)+log_{10}(9)=1
The solution is x=-62/9