What is the answer to log_{2}(4x)=8log_{x}(2) ?

The answer to log_{2}(4x)=8log_{x}(2) is x=4,x= 1/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(4x)=8log_{x}(2)

lo g_{2} (4 x) = 8 lo g_{x} (2)

x = 4, x = \frac{1}{16}

Decimal Notation

x = 4, x = 0.0625

Solution steps

lo g_{2} (4 x) = 8 lo g_{x} (2)

Apply log rules

lo g_{2} (4) + lo g_{2} (x) = \frac{8}{lo g _{2} ( x )}

Rewrite the equation with

lo g_{2} (x) = u

lo g_{2} (4) + u = \frac{8}{u}

Solve

lo g_{2} (4) + u = \frac{8}{u} : u = 2, u = - 4

u = 2, u = - 4

Substitute back

u = lo g_{2} (x),

solve for

x

Solve

lo g_{2} (x) = 2 : x = 4

Solve

lo g_{2} (x) = - 4 : x = \frac{1}{16}

x = 4, x = \frac{1}{16}

Verify Solutions:

x = 4

True

, x = \frac{1}{16}

True

The solutions are

x = 4, x = \frac{1}{16}

lo g_{3} (x^{2}) = 4

ln (x + 2) = 2

ln (x) + ln (x + 2) = ln (3)

0.62 = lo g_{10} (x)

lo g_{10} (x) = 100

What is the answer to log_{2}(4x)=8log_{x}(2) ?
The answer to log_{2}(4x)=8log_{x}(2) is x=4,x= 1/16
Solve for x: log_{2}(4x)=8log_{x}(2)
The solution is x=4,x= 1/16