What are the solutions to the equation (x+5)^2=4 ?

The solutions to the equation (x+5)^2=4 are x=-3,x=-7

Find the zeros of (x+5)^2=4

The zeros of (x+5)^2=4 are x=-3,x=-7

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(x + 5)^{2} = 4

x = - 3, x = - 7

Solution steps

(x + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 4 : x = - 3

Solve

x + 5 = - 4 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

3 x^{2} + 31 x + 36

a^{3} - a^{2} - a + 1

\frac{11 !}{( 11 - 6 ) ! 6 !}

- x^{2} + 4 > 0

(a^{- 4})^{2}

What are the solutions to the equation (x+5)^2=4 ?
The solutions to the equation (x+5)^2=4 are x=-3,x=-7
Find the zeros of (x+5)^2=4
The zeros of (x+5)^2=4 are x=-3,x=-7