What is the answer to ln(x^2)-0.7=0 ?

The answer to ln(x^2)-0.7=0 is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}

Solve for x: ln(x^2)-0.7=0

The solution is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}

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ln (x^{2}) - 0.7 = 0

x = e^{0.7}, x = - e^{0.7}

Solution steps

ln (x^{2}) - 0.7 = 0

Move

0.7

to the right side

ln (x^{2}) = 0.7

Apply log rules

x^{2} = e^{0.7}

Solve

x^{2} = e^{0.7} : x = e^{0.7}, x = - e^{0.7}

x = e^{0.7}, x = - e^{0.7}

Verify Solutions:

x = e^{0.7}

True

, x = - e^{0.7}

True

The solutions are

x = e^{0.7}, x = - e^{0.7}

0.69 = lo g_{10} (x)

3 ln (2 x) - 4 = 2 ln (2 x)

ln (4 x + 2) = 3

lo g_{2} (2 x - 3) = 4

0.76 = lo g_{10} (x)

What is the answer to ln(x^2)-0.7=0 ?
The answer to ln(x^2)-0.7=0 is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}
Solve for x: ln(x^2)-0.7=0
The solution is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}