What is the answer to ln(x+1)=log_{2}(3) ?

The answer to ln(x+1)=log_{2}(3) is x=e^{log_{2}(3)}-1

Solve for x: ln(x+1)=log_{2}(3)

The solution is x=e^{log_{2}(3)}-1

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ln (x + 1) = lo g_{2} (3)

x = e^{l o g_{2} (3)} - 1

Decimal Notation

x = 3.87910 \dots

Solution steps

ln (x + 1) = lo g_{2} (3)

Apply log rules

x + 1 = e^{l o g_{2} (3)}

Solve

x + 1 = e^{l o g_{2} (3)} : x = e^{l o g_{2} (3)} - 1

x = e^{l o g_{2} (3)} - 1

lo g_{2} (x + 2) - lo g_{2} (x - 1) = 1

6 ln (4 x - 10) - 2 = 40

ln (x) + ln (x - 2) = 4

ln (x^{4}) = 24

ln (x + 1) = 2 - ln (x - 1)

What is the answer to ln(x+1)=log_{2}(3) ?
The answer to ln(x+1)=log_{2}(3) is x=e^{log_{2}(3)}-1
Solve for x: ln(x+1)=log_{2}(3)
The solution is x=e^{log_{2}(3)}-1