What is the answer to log_{5}(x^2+x+4)=2 ?

The answer to log_{5}(x^2+x+4)=2 is x=(-1+sqrt(85))/2 ,x=(-1-sqrt(85))/2

Solve for x: log_{5}(x^2+x+4)=2

The solution is x=(-1+sqrt(85))/2 ,x=(-1-sqrt(85))/2

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lo g_{5} (x^{2} + x + 4) = 2

x = \frac{- 1 + 85}{2}, x = \frac{- 1 - 85}{2}

Decimal Notation

x = 4.10977 \dots, x = - 5.10977 \dots

Solution steps

lo g_{5} (x^{2} + x + 4) = 2

Apply log rules

x^{2} + x + 4 = 25

Solve

x^{2} + x + 4 = 25 : x = \frac{- 1 + 85}{2}, x = \frac{- 1 - 85}{2}

x = \frac{- 1 + 85}{2}, x = \frac{- 1 - 85}{2}

lo g_{3} (x - 6) = lo g_{9} (x)

lo g_{9} (x) = - \frac{1}{2}

lo g_{2} (x^{2} - x) = 1

lo g_{x} (256) = 4

lo g_{10} (x) = - 2.2118

What is the answer to log_{5}(x^2+x+4)=2 ?
The answer to log_{5}(x^2+x+4)=2 is x=(-1+sqrt(85))/2 ,x=(-1-sqrt(85))/2
Solve for x: log_{5}(x^2+x+4)=2
The solution is x=(-1+sqrt(85))/2 ,x=(-1-sqrt(85))/2